squaring binomial irrationals

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Motherof8
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squaring binomial irrationals

Postby Motherof8 » Tue Jun 21, 2011 2:12 am

The problem is 1- the square root of 3 /2 squared. When you work it out it is 1-2xthe square root of 3 + 3/4. They say the final answer is 2 - the square root of 3 /2. I can see how they got the other numbers, but how did they get the 2 on the bottom?

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stapel_eliz
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Postby stapel_eliz » Tue Jun 21, 2011 10:14 am

Motherof8 wrote:The problem is 1- the square root of 3 /2 squared.

Does the above mean the following?

. . . . .

Were the instructions to "simplify"?

Thank you! :wink:

Motherof8
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Re: squaring binomial irrationals

Postby Motherof8 » Wed Jun 22, 2011 12:02 am

Actually, the problem was (1- the square root of 3) over 2. The whole thing is in parenthesis and is squared. I hope this makes it clearer.

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stapel_eliz
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Postby stapel_eliz » Wed Jun 22, 2011 3:41 pm

Motherof8 wrote:Actually, the problem was (1- the square root of 3) over 2. The whole thing is in parenthesis and is squared. I hope this makes it clearer.

So the expression is as follows?

. . . . .

And the instructions were to "simplify"?

When you reply, please include the steps in your work (between the exercise and your simplified form), so we can try to find any errors. Thank you! :wink:

Motherof8
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Re: squaring binomial irrationals

Postby Motherof8 » Wed Jun 22, 2011 11:58 pm

Yes, that was the right expression. I multiplied ()1-the square root of 3) over 2 by itself. I got1 -2 x the square root of 3+3 over 4. Simplified,3-2 =1 +1 =2, but why is the four on the bottom reduced to a 2?

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stapel_eliz
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Postby stapel_eliz » Thu Jun 23, 2011 10:35 am

Motherof8 wrote:Yes, that was the right expression. I multiplied ()1-the square root of 3) over 2 by itself. I got1 -2 x the square root of 3+3 over 4. Simplified,3-2 =1 +1 =2...

How did:

. . . . .

...turn into "2"? What happened to the square root? :confused:


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