The book gives an answer of . This is probably very simple problem but I really don't understand how to workout a problem like that.

I would appreciate if anyone would like to show the steps involved getting to that answer and maybe point to a related lesson

- stapel_eliz
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Beini wrote:I really don't understand how to workout a problem like that.

To learn, please try

First, simplify the complex fraction (the part after the initial "x minus"). A good first step for this will be to multiply, top and bottom, by "x + 1":

. . . . .

Then convert the linear term into fractional form, having a common denominator. Then combine and simplify.

Beini wrote:

The book gives an answer of . This is probably very simple problem but I really don't understand how to workout a problem like that.

I would appreciate if anyone would like to show the steps involved getting to that answer and maybe point to a related lesson

It's been a few days so I'm going to work the problem out how I would do it. I would start by getting rid of the complex fraction by flipping the bottom and multiplying.

The starting equation.

Flip the bottom and multiply.

Multiply the second term.

Then I would get a common denominator, which will be x:

Multiplying the first term by (x/x) to get the common denominator.

Done the multiplication.

Combined the fractions for subtraction since we have a common denominator.

Difference of squares identity where (x+1)(x-1) = x² - 1.

Distribute the negative.

Simplify the numerator.

Ta da!