lim,h->0,{(2+h)^3 - 8}/h gives f' at some "a". Find f, a.

[nona.m.nona]

The limit, as h approaches 0, of {(2 + h)³ - 8} / h represents the derivative of some f(x) at some point a. Find f(x) and a.

Since 2³ = 8, and since the formula for f'(x) is {f(x + h) - f(x)} / h as h goes to 0, is this just f(x) = x³ with a = 2?

[stapel_eliz]

...is this just f(x) = x³ with a = 2?

That's how I would read this. Good job!