simplifying [L]/([L/v])^2 (trying to remove the square)  TOPIC_SOLVED

Simplificatation, evaluation, linear equations, linear graphs, linear inequalities, basic word problems, etc.

simplifying [L]/([L/v])^2 (trying to remove the square)

Postby dwhite8625 on Wed May 18, 2011 1:36 am

having trouble with simplifying
[L]/([L/v])^2
i am trying to remove the square in the denominator
dwhite8625
 
Posts: 1
Joined: Wed May 18, 2011 1:30 am

Sponsor

Sponsor
 

Postby stapel_eliz on Wed May 18, 2011 10:54 am

dwhite8625 wrote:having trouble with simplifying
[L]/([L/v])^2
i am trying to remove the square in the denominator

What do you mean by "removing" the square? Are you maybe trying to "simplify" by removing the parentheses? :confused:

Simplifying with Exponents
User avatar
stapel_eliz
 
Posts: 1720
Joined: Mon Dec 08, 2008 4:22 pm

Re: simplifying [L]/([L/v])^2 (trying to remove the square)  TOPIC_SOLVED

Postby jcol2026 on Fri May 20, 2011 2:23 pm

here it is
1st remember that 2/5 is the same as 2*(1/5)
so [L]/([L/v])^2 becomes [L]*([v/L])^2

= (Lv^2)/L^2

= v^2/L


hope this helps
jcol2026
 
Posts: 1
Joined: Fri May 20, 2011 2:11 pm


Return to Beginning Algebra

cron