Helping students gain understanding and self-confidence in algebra.
Motherof8 wrote:The side of one square exceeds that of another by 3 inches. Its area exceeds twice the area of other by 17 square inches. Find the lengths of their sides.
I used this formula:
(x + 3) squared = 2x squared + 17 squared
x squared + 6x + 9 = 2x squared + 289
2x squared -x squared -6x -9 + 289 = 0
x squared -6x + 280
Motherof8 wrote:2x squared - x squared = x squared. 289 -9 = 280, leaving x squared -6x +280.