What is the closed form for recursive equation [a][/0] = 0, [a][/1] = 1 and [a][/n] = [3a][/n-1] - [2a][/n-2]

is the closed form [a][/k+1] = [3a][/k+1-1] - [2a][/k+1-2] ???

What is the closed form for recursive equation [a][/0] = 0, [a][/1] = 1 and [a][/n] = [3a][/n-1] - [2a][/n-2]

is the closed form [a][/k+1] = [3a][/k+1-1] - [2a][/k+1-2] ???

is the closed form [a][/k+1] = [3a][/k+1-1] - [2a][/k+1-2] ???

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- Martingale
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hbelle wrote:What is the closed form for recursive equation [a][/0] = 0, [a][/1] = 1 and [a][/n] = [3a][/n-1] - [2a][/n-2]

is the closed form [a][/k+1] = [3a][/k+1-1] - [2a][/k+1-2] ???

if you had

then the closed form is just