What is the closed form for recursive equation [a][/0] = 0, [a][/1] = 1 and [a][/n] = [3a][/n-1] - [2a][/n-2]

is the closed form [a][/k+1] = [3a][/k+1-1] - [2a][/k+1-2] ???

What is the closed form for recursive equation [a][/0] = 0, [a][/1] = 1 and [a][/n] = [3a][/n-1] - [2a][/n-2]

is the closed form [a][/k+1] = [3a][/k+1-1] - [2a][/k+1-2] ???

is the closed form [a][/k+1] = [3a][/k+1-1] - [2a][/k+1-2] ???

- stapel_eliz
**Posts:**1731**Joined:**Mon Dec 08, 2008 4:22 pm-
**Contact:**

- Martingale
**Posts:**350**Joined:**Mon Mar 30, 2009 1:30 pm**Location:**USA-
**Contact:**

hbelle wrote:What is the closed form for recursive equation [a][/0] = 0, [a][/1] = 1 and [a][/n] = [3a][/n-1] - [2a][/n-2]

is the closed form [a][/k+1] = [3a][/k+1-1] - [2a][/k+1-2] ???

if you had

then the closed form is just