What is the closed form for recursive equation [a][/0] = 0, [a][/1] = 1 and [a][/n] = [3a][/n-1] - [2a][/n-2]
is the closed form [a][/k+1] = [3a][/k+1-1] - [2a][/k+1-2] ???
hbelle wrote:What is the closed form for recursive equation [a][/0] = 0, [a][/1] = 1 and [a][/n] = [3a][/n-1] - [2a][/n-2]
hbelle wrote:What is the closed form for recursive equation [a][/0] = 0, [a][/1] = 1 and [a][/n] = [3a][/n-1] - [2a][/n-2]
is the closed form [a][/k+1] = [3a][/k+1-1] - [2a][/k+1-2] ???