1 < 4x + 3 < 9

Can anyone help me understand this problem? I need to solve and apply interval notation.

1 < 4x + 3 < 9

- stapel_eliz
**Posts:**1628**Joined:**Mon Dec 08, 2008 4:22 pm-
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How would you solve "4x + 3 = 9"? How about solving "1 = 4x + 3"? You use much the same methods forCan anyone help me understand this problem? I need to solve and apply interval notation.

1 < 4x + 3 < 9

For instance:

. . . . .-2 < 3x + 4 < 13

. . . . .-2 - 4 < 3x + 4 - 4 < 13 - 4

. . . . .-6 < 3x < 9

. . . . .(-6)/3 < (3x)/3 < 9/3

. . . . .-2 < x < 3

The "interval notation" presentation of the above solution would be "(-2, 3)". Follow the same pattern with your exercise.