Okay, so I'm still trying to wrap my head around this one, but I think I understand enough to make another post.
What we have normally dealt with is a limit being super super simple, like

To show that Y never actually
is 1, but is always getting closer to it.
Now, the problem is asking me to show how Y is always approaching 6x-1 but never actually is.
Alright... I can do that.
So I start with my original function.
=3x^2-x-1)
=6x-1)
Now I make a little chart to show values to compare them.
When x=1
=1)
=5)
When x=10
=289)
=59)
But now I am immediately confused, because while this is
normally how we showed that this was where the function never crossed we can see that it clearly does. Meaning that there is a point where f(x)=f'(x) and it's between 1&10 (I didn't take the time to find the exact point). How is this a "limit" if it does in fact cross over?
I'm not really sure where the
-f(x)}{h})
is coming from. I'm assuming that's the general equation for a derivative?
So do I just plug all that in and solve for 6x-1?
What is h supposed to equal? 6x-1?
^2-(6x-1)-1))-(3x^2-x-1)}{6x-1})
I don't have time at the moment, but I'll be back in an hour and solve this one...