If X+Y+Z=35000, X+38% of Z=11900, Y+62% of Z=23100, find Z  TOPIC_SOLVED

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If X+Y+Z=35000, X+38% of Z=11900, Y+62% of Z=23100, find Z

Postby Madhuri hadwale on Wed Mar 02, 2011 10:34 am

Hello,

I having problem in arithmatic Equation can anybody help me.

EX
If
X+Y+Z=35000
X+38% of Z=11900
Y + 62% of Z =23100

Than Z=??????
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Re: If X+Y+Z=35000, X+38% of Z=11900, Y+62% of Z=23100, find  TOPIC_SOLVED

Postby maggiemagnet on Wed Mar 02, 2011 12:13 pm

Madhuri hadwale wrote:If
X+Y+Z=35000
X+38% of Z=11900
Y + 62% of Z =23100

Than Z=??????

Turn the "38%" into a decimal: 0.38. Turn the "of" into "times". So you have "X + 0.38Z = 11900".

Now do the same thing with the third equation. And then solve the second equation for "X=" and the third equation for "Y=". Plug these in for "X" and "Y" in the first equation.

You can solve this for "Z=". :thumb:
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