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by crescentcitycid on Sun Feb 27, 2011 10:28 pm
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by stapel_eliz on Sun Feb 27, 2011 10:40 pm
crescentcitycid wrote:If I had the function R=2.3log(A+3000)-5.1 and I wanted solve for A in terms of R, would A=10^{((R/2.3)-5.1))}-3000 be correct?
by crescentcitycid on Sun Feb 27, 2011 10:57 pm
by stapel_eliz on Mon Feb 28, 2011 12:50 am
crescentcitycid wrote:Ah, I should start with adding the 5.1 then?
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