solve by substitution: x=5y - 2, 2x + y = -4

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buddy
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solve by substitution: x=5y - 2, 2x + y = -4

Postby buddy » Sun Mar 01, 2009 10:21 pm

Solve the system using the substituation method...
x=5y - 2
2x + y = -4
not sure of what im doing?

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stapel_eliz
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Postby stapel_eliz » Sun Mar 01, 2009 10:52 pm

buddy wrote:Solve the system using the substituation method...
x=5y - 2
2x + y = -4
not sure of what im doing?

To "solve by substitution", you substitute from one equation into the other. In your case, the first equation is already solved for "x=", so plug the other side of that equation, the "5x - 2", in for the "x" in the second equation:

. . . . .2(5y - 2) + y = -4

Can you take it from there? :wink:

buddy
Posts: 158
Joined: Sun Feb 22, 2009 10:05 pm
Contact:

Re: solve by substitution: x=5y - 2, 2x + y = -4

Postby buddy » Mon Mar 02, 2009 6:45 pm

y=0
x=0-2=-2
thnx


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