Please help having a difficult time solving this problem! The perimeter of a rectangle is 58 inches. The length exceeds the width by 19 inches. Find the length and width.
phansen05 wrote:Please help having a difficult time solving this problem! The perimeter of a rectangle is 58 inches. The length exceeds the width by 19 inches. Find the length and width.
The formula for perimeter is P = 2L + 2W You know that P = 58 and W + 19 = L Replace the L in the first equation with (W + 19) Solve for W and then add 19 to get L.