I am having difficulty finding integral((tanx)^2 / (secx)^2)dx.
I tried converting everything in terms of sinx and cosx but that doesn't seem to help.
Andromeda wrote:I am having difficulty finding integral((tanx)^2 / (secx)^2)dx.
I tried converting everything in terms of sinx and cosx but that doesn't seem to help.
stapel_eliz wrote:Andromeda wrote:I am having difficulty finding integral((tanx)^2 / (secx)^2)dx.
I tried converting everything in terms of sinx and cosx but that doesn't seem to help.
Once you've simplified and gotten an expression in just sine, you can use the double-angle formula (in reverse) for the cosine:
. . . . .
Then the integral is pretty straightforward.
Note: You will be using the double-angle formulas (in reverse) a lot in calculus, so make sure you're solid on them!