QUESTION:To avoid detection at customs a traveler places 6 narcotics tablets in a bottle containg 9 vitamin pills that are similar in appearance.The the custom offical selects two of the tablets at random for analysis, what is the probability that the traveler will be arrested for illegal possesion of narcotics?

well i figured: probability of finding the drug in the first pill is 6/15 and the probability of find the drug in the next pill is 5/14.

Probability of finding the drug in at least one of the pills is 6/15 + 5/14 -(6/15 * 5/14) = 159/210 - 30/210 = 129/210=0.614 = 61.4%

????

Please let me know if i'm doing it wrong???