Help to solve this:
If x/a=y/b=z/c, a+b+c=1 and a^2+b^2+ c^2=1. Prove: xy+yz+zx=0
japiga wrote:Help to solve this:
If x/a=y/b=z/c, a+b+c=1 and a^2+b^2+ c^2=1. Prove: xy+yz+zx=0
japiga wrote::confused: And then? How to include this in the first equation x/a=y/b=z/c ?
japiga wrote:But what is a purpose of plugging into the equation of xy + yz + zx? Actually, how to reach this equation?
japiga wrote:... So x= (az)/c and y=(bz)/c. Does it what you mean?
japiga wrote:...So x= (az)/c and y=(bz)/c. Does it what you mean?
japiga wrote:Sorry, but it is not so helpful!
Please give me step by step procedure.