I am studying for an exam and I don't you know how to go about this?
Volume of solid under the curve y= 7/(x^2 +5x +6) from x = 0 to x = 1 if rotated about the y-axis.
I made x the subject of the formula getting (sqrt(y+28)-5 sqrt(y))/(2 sqrt(y)) and then I found what y is when x= 0 and x=1, which were y=7/6 and y=7/12 respectively.
then I integrated using (pi*(f(y))^2*dy); pi*((sqrt(y+28)-5 sqrt(y))/(2 sqrt(y)))^2 to get the volume then I got
pi*(-7/12+105 log(2)-70 log(3)+log(128)) which is aprroximately 0.46.
I know the answer isn't correct because I checked the answers on my text book. Plz help me understand this problem