How would you evaluate this integral ?
x^2/(36-x^2)^(3/2)
Parts or Substitution ?(I tried using substitution) Please explain.
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how to integrate x^2/(36-x^2)^(3/2): parts or substitution? 
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how to integrate x^2/(36-x^2)^(3/2): parts or substitution?
by chinex9a on Fri Sep 24, 2010 9:21 pm
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Re: x^2/(36-x^2)^(3/2) 
by nona.m.nona on Sat Sep 25, 2010 12:12 am
I would suggest using substitution: x = 6*sin(u).
Wolfram: http://www.wolframalpha.com/input/?i=integrate+%28x^2%29%2F%2836-x^2%29^%283%2F2%29
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Wolfram: http://www.wolframalpha.com/input/?i=integrate+%28x^2%29%2F%2836-x^2%29^%283%2F2%29
(copy and paste the above into your browser's location bar)
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