buddy wrote:factor x^-1/2 + x^5/2
the -1/2 and 5/2 are powers
To format this clearly
, use grouping symbols:. . . . .
x^(-1/2) + x^(5/2)
You can also use the "sup" tags (from the formatting line above the message-entry box):. . . . .
...displays as:. . . . .
buddy wrote:i dont see how anything comes out?
Nothing much does, actually...
Use exponent rules
to convert the negative-powered term to a fraction:. . . . .. . . . .
You might find it easy, by the way, to convert the fractional powers to radical form, while you're doing your steps:. . . . .. . . . .
The common denominator is the square root of x, but of course you're not supposed to have radicals in the denominator, so let's "rationalize" that first:. . . . .. . . . .
Now the common denominator would be x, so:. . . . .. . . . .
The only common factor is the radical:. . . . .Factor the sum of cubes
, and I think you're done!