burnbird16 wrote:But that's what I had originally, and I can't solve for y. Please, explain.
you can't solve...
Martingale wrote:
we know
so replace with
and solve for
for
subtract the then take the square root of both sides.
burnbird16 wrote:But that's what I had originally, and I can't solve for y. Please, explain.
Martingale wrote:
we know
so replace with
and solve for
burnbird16 wrote:Oh, wait, I think I get it! do , then solve that for y! Awesome. Now, I only have one more problem...but it's in six parts. Basically, they are using simple trigonometric identities to create new ones. But I don't know how to get there. For example, I am to produce using
burnbird16 wrote:Ugh, yet more issues arise.
How do I produce using the same identity as before?
burnbird16 wrote:Ugh, yet more issues arise.
How do I produce using the same identity as before? Also, how would I produce ?
burnbird16 wrote:One tiny question though. How does the absolute value come into play? I'm to that point, but I don't understand the purpose of the absolute value there, or how to get it there.