how many litres of water in pool 5ft deep w/ diam. of 20 ft

[frankie10]

A pool chemical requires you to add 700g of the chemical for every 20 000L of water in the pool.Your pool is above ground,5ft deep,and round,with a diameter of 20ft.

how many litres of water would be in this pool?

[stapel_eliz]

A pool chemical requires you to add 700g of the chemical for every 20 000L of water in the pool.Your pool is above ground,5ft deep,and round,with a diameter of 20ft.

how many litres of water would be in this pool?

What is the radius of the pool? What then is the cross-sectional area of the pool?

What is the height of the pool? What then is the volume of the pool?

If you get stuck, please reply showing how far you have gotten in following the steps. Thank you!

[frankie10]

the radius is 10 and the height is 5

[stapel_eliz]

the radius is 10...

So what is the cross-sectional area of the base?

...and the height is 5

So what is the volume?

[frankie10]

v=pi*r^2 * h
v=3.14*(5)(10)^2
v=3.14(5)100
v=1570

[stapel_eliz]

Now you have the cubic feet. What conversion factor did they give you for converting cubic feet to liters?

[frankie10]

1570*28.316=44456.12

[stapel_eliz]

Don't forget the units on your answer!

[frankie10]

A pool chemical requires you to add 700g of the chemical for every 20 000L of water in the pool.Your pool is above ground,5ft deep,and round,with a diameter of 20ft.

how many litres of water would be in this pool?

v=pi*r^2 * h
v=3.14*(5)(10)^2
v=3.14(5)100
v=1570

in the book it says (remember 1m^3 of water is 1000L)

so therefore 1570*1000=1570000
so there's 1570000 l of water in the pool.


Can someone tell me if this is right

[stapel_eliz]

v=1570

in the book it says (remember 1m^3 of water is 1000L)

so therefore 1570*1000=1570000

Why are you multiplying your cubic-foot measure by the conversion factor for cubic meters?