Suppose X and Y are independent Poisson random variable , each with the mean 1 , obtain

i) P(X+Y=4)

ii) E[(X+Y)

^{2}]

Question :

Suppose X and Y are independent Poisson random variable , each with the mean 1 , obtain

i) P(X+Y=4)

ii) E[(X+Y)^{2}]

Suppose X and Y are independent Poisson random variable , each with the mean 1 , obtain

i) P(X+Y=4)

ii) E[(X+Y)

- Martingale
**Posts:**344**Joined:**Mon Mar 30, 2009 1:30 pm**Location:**USA-
**Contact:**

zorro wrote:Question :

Suppose X and Y are independent Poisson random variable , each with the mean 1 , obtain

i) P(X+Y=4)

ii) E[(X+Y)^{2}]

Start with this...http://en.wikipedia.org/wiki/Poisson_distribution#Properties

Martingale wrote:zorro wrote:Question :

Suppose X and Y are independent Poisson random variable , each with the mean 1 , obtain

i) P(X+Y=4)

ii) E[(X+Y)^{2}]

Start with this...http://en.wikipedia.org/wiki/Poisson_distribution#Properties

Thanks

so = = 1

P(A+B=4) = ?

- Martingale
**Posts:**344**Joined:**Mon Mar 30, 2009 1:30 pm**Location:**USA-
**Contact:**

zorro wrote:Martingale wrote:zorro wrote:Question :

Suppose X and Y are independent Poisson random variable , each with the mean 1 , obtain

i) P(X+Y=4)

ii) E[(X+Y)^{2}]

Start with this...http://en.wikipedia.org/wiki/Poisson_distribution#Properties

Thanks

so = = 1

P(A+B=4) = ?_{stuck here !!!}

From the link I provided look at "Sums of Poisson-distributed random variables"

Martingale wrote:zorro wrote:Martingale wrote:Start with this...http://en.wikipedia.org/wiki/Poisson_distribution#Properties

Thanks

so = = 1

P(A+B=4) = ?_{stuck here !!!}

From the link I provided look at "Sums of Poisson-distributed random variables"

I couldnt understand how to evaluate P(A+B=4) as

is it P(A+B=4) = P(A) + P(B) = 4

or is it some other way

- Martingale
**Posts:**344**Joined:**Mon Mar 30, 2009 1:30 pm**Location:**USA-
**Contact:**

zorro wrote:

I couldnt understand how to evaluate P(A+B=4) as

is it P(A+B=4) = P(A) + P(B) = 4

or is it some other way

If X is poisson 1 and Y is poisson 1

then X+Y is Poisson 2

Martingale wrote:zorro wrote:

I couldnt understand how to evaluate P(A+B=4) as

is it P(A+B=4) = P(A) + P(B) = 4

or is it some other way

If X is poisson 1 and Y is poisson 1

then X+Y is Poisson 2

but how should i represent it in my solution

P(A+B) = 1+1 = 2 but what about the '4'

I am having a hard time how to formulate this ? sorry or such silly questions?

- Martingale
**Posts:**344**Joined:**Mon Mar 30, 2009 1:30 pm**Location:**USA-
**Contact:**

zorro wrote:

but how should i represent it in my solution

P(A+B) = 1+1 = 2 but what about the '4'

I am having a hard time how to formulate this ? sorry or such silly questions?

I think you need to review the basics of probability before you start working with random variables. I really think it will help you since your foundation in the basics is not strong enough.

Good luck!