Question :
Suppose X and Y are independent Poisson random variable , each with the mean 1 , obtain
i) P(X+Y=4)
ii) E[(X+Y)^{2}]
zorro wrote:Question :
Suppose X and Y are independent Poisson random variable , each with the mean 1 , obtain
i) P(X+Y=4)
ii) E[(X+Y)^{2}]
Martingale wrote:zorro wrote:Question :
Suppose X and Y are independent Poisson random variable , each with the mean 1 , obtain
i) P(X+Y=4)
ii) E[(X+Y)^{2}]
Start with this...http://en.wikipedia.org/wiki/Poisson_distribution#Properties
zorro wrote:Martingale wrote:zorro wrote:Question :
Suppose X and Y are independent Poisson random variable , each with the mean 1 , obtain
i) P(X+Y=4)
ii) E[(X+Y)^{2}]
Start with this...http://en.wikipedia.org/wiki/Poisson_distribution#Properties
Thanks
so = = 1
P(A+B=4) = ? _{stuck here !!!}
Martingale wrote:zorro wrote:Martingale wrote:Start with this...http://en.wikipedia.org/wiki/Poisson_distribution#Properties
Thanks
so = = 1
P(A+B=4) = ? _{stuck here !!!}
From the link I provided look at "Sums of Poisson-distributed random variables"
zorro wrote:
I couldnt understand how to evaluate P(A+B=4) as
is it P(A+B=4) = P(A) + P(B) = 4
or is it some other way
Martingale wrote:zorro wrote:
I couldnt understand how to evaluate P(A+B=4) as
is it P(A+B=4) = P(A) + P(B) = 4
or is it some other way
If X is poisson 1 and Y is poisson 1
then X+Y is Poisson 2
zorro wrote:
but how should i represent it in my solution
P(A+B) = 1+1 = 2 but what about the '4'
I am having a hard time how to formulate this ? sorry or such silly questions?