Problem: f(x) = 2x^3-x^2-x/x^2-4

I need to divide this using long division and don't know how to get passed the first step...can you help.

Problem: f(x) = 2x^3-x^2-x/x^2-4

I need to divide this using long division and don't know how to get passed the first step...can you help.

I need to divide this using long division and don't know how to get passed the first step...can you help.

- stapel_eliz
**Posts:**1670**Joined:**Mon Dec 08, 2008 4:22 pm-
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aranda5 wrote:Problem: f(x) = 2x^3-x^2-x/x^2-4

As

. . . . .

However, I think the function may actually be as follows:

. . . . .

Please confirm or correct.

aranda5 wrote:I need to divide this using long division and don't know how to get passed the first step.

To learn how to use long polynomial division, try

Note: You may want to put " inside your division, to help make room for the various terms you'll have when you do the subtractions.

If you get stuck, please reply showing your steps and reasoning so far. It will probably prove helpful to use "pre" tags for your formatting, like this:

Code: Select all

`[pre]my work:`

2x

----------------------

x^2 - 4 ) 2x^3 - 1x^2 - 1x + 0

2x^3 - 8x

----------------------

- 1x^2 + 7x + 0[/pre]

...which displays as:

my work:

2x

----------------------

x^2 - 4 ) 2x^3 - 1x^2 - 1x + 0

2x^3 - 8x

----------------------

- 1x^2 + 7x + 0

Thank you!