I have 3 raised to the (x^2 - 1) / 9 raised to (x + 2) = one-nineth.
So first I set up common bases. I have 3 raised to the (x^2 - 1) divided by 3 raised to the (2x + 4) = one-nineth. Now I am stuck. I have the same bases but am I suppose subtract the exponents? Can someone please help me get over this hump?
rogermiranda wrote:So first I set up common bases.
What must be the value of , for What must be the value of , for
By using this information to convert the right-hand side to a fraction in powers of 3 (or alternatively, using exponent rules to convert each side to possibly negative powers of 3), you can set up an equivalence that you can solve for the value(s) of