Triangle ABC is a right triangle, with B being the right angle and line CB being the ground. An obtuse triangle is inside triangle ABC. Let's call this obtuse triangle ADC.
The diagram should look something like this:
Suppose angle ACB=24.4 degrees and angle ADB=58.3 degrees, and CB=169 units.
AB should 106.5 units, but how do you solve this? Please explain the steps using sine, cosine and tangent ratios involving a right triangle.
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