Hey, I know how to solve equations with variables, but not when they involve fractions. I have a problem like this: R= I need to "Solve for B". How would I do that? Please reply as soon as possible.

Thanks, iceking

Hey, I know how to solve equations with variables, but not when they involve fractions. I have a problem like this: R= I need to "Solve for B". How would I do that? Please reply as soon as possible.

Thanks, iceking

Thanks, iceking

- stapel_eliz
**Posts:**1670**Joined:**Mon Dec 08, 2008 4:22 pm-
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The steps for solving equations with fractions are the same as for solving equations without. Where are you getting stuck?

Note: Since this "fraction" is of the form "divided by one", you can ignore the denominator and simply solve "R = x(A + B)" in**the usual manner**.

Note: Since this "fraction" is of the form "divided by one", you can ignore the denominator and simply solve "R = x(A + B)" in

stapel_eliz wrote:The steps for solving equations with fractions are the same as for solving equations without. Where are you getting stuck?

Note: Since this "fraction" is of the form "divided by one", you can ignore the denominator and simply solve "R = x(A + B)" inthe usual manner.

Thanks, so now I have the equation "R=xa+xb". Should I divide both sides by x? If so, then I would have the equation " = A+B" .

Then what? Would I then subtract "A" from both sides to get the equation -A=B ? The only answer choices I have are:

B=(R-A)/x and B=(A-Rx)/x and B=(R-Ax)/x . I need to figure out Which equation would get me to the value of "B"

- stapel_eliz
**Posts:**1670**Joined:**Mon Dec 08, 2008 4:22 pm-
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Work with the algebra, and see which of the answer-options matches your answer. The only difference is one of formatting: they did the addition/subtraction to isolate the B-term first, whereas you went the (usually harder) route of doing the multiplication/division first.

But your answer*does* match one of the given options.

But your answer

stapel_eliz wrote:Work with the algebra, and see which of the answer-options matches your answer. The only difference is one of formatting: they did the addition/subtraction to isolate the B-term first, whereas you went the (usually harder) route of doing the multiplication/division first.

But your answerdoesmatch one of the given options.

I tried the addition/subtraction this time, and I got the equation "xB=R-xA" Then I divided both sides by "x" " = " Then simplyfying that, I got: " B= " Is this the correct equation?

- stapel_eliz
**Posts:**1670**Joined:**Mon Dec 08, 2008 4:22 pm-
**Contact:**

Thanks for all your help!