Not sure how to solve this for x is the element of the real number system:

x^3 = x^2 + 4x

Not sure how to solve this inequality

x^3 = 33 < 0

Not sure how to solve this for x is the element of the real number system:

x^3 = x^2 + 4x

Not sure how to solve this inequality

x^3 = 33 < 0

x^3 = x^2 + 4x

Not sure how to solve this inequality

x^3 = 33 < 0

- stapel_eliz
**Posts:**1628**Joined:**Mon Dec 08, 2008 4:22 pm-
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Follow the usual procedure: Get everything over onto one side of the "equals" sign, factor, and then try to solve the factors.Not sure how to solve this for x is the element of the real number system:

x^3 = x^2 + 4x

. . . . .x

. . . . .x(x

The first factor, the x, "solves" simply enough: x = 0.

For the other factor, the x

Not sure how to solve this inequality

x^3 = 33 < 0

Since thirty-three isn't less than zero, I have no idea what they want, either!

Please ask your instructor for corrections or clarification. Thank you!

Eliz.

Thanks for the help and for the inequality I meant to write x^3 + 3x < 0 Sorry.

- stapel_eliz
**Posts:**1628**Joined:**Mon Dec 08, 2008 4:22 pm-
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Ah; that makes more sense!for the inequality I meant to write x^3 + 3x < 0

You've got a cubic, which I'm sure you're quite used to graphing. If you think about the graph of y = x

So you've got a cubic that crosses the x-axis exactly once. This is a positive cubic (the leading coefficient is an "understood" +1), so the graph comes up from the bottom on the left, crosses the x-axis at x = 0, and then heads up to the right. There may be a "squiggle" in the middle somewhere.

With this zero in mind, what are the two intervals for this inequality? (That is, what are the two parts of the number line where the cubic isn't zero?)

With this graph in mind, on which of those those intervals is the cubic negative? (That is, on which interval is the graph below the x-axis?)

That interval is your solution. Remember to include the point x = 0 in your solution interval, since this is an "or equal to" inequality.

Eliz.