If cos 'theta' =1/2 the sin'theta' = WHAT?  TOPIC_SOLVED

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If cos 'theta' =1/2 the sin'theta' = WHAT?

Postby rere on Thu Jul 23, 2009 11:58 pm

Help please...

If 90 degrees < 'theta' <180 degrees what is equaled to 5 cos 'theta' sec 'theta'?

and another...

If cos 'theta' =1/2 the sin'theta' = WHAT?

thank you for any advice and help.
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Postby stapel_eliz on Fri Jul 24, 2009 12:03 am

rere wrote:If 90 degrees < 'theta' <180 degrees what is equaled to 5 cos 'theta' sec 'theta'?

I'm sorry, but I don't understand what this exercise is asking...? Are you supposed to find a range of value for the product of the 5, the cosine, and the secant? Or something else?

rere wrote:If cos 'theta' =1/2 the sin'theta' = WHAT?

Draw the right triangle. Label "adjacent" and "hypotenuse" sides with the values from the cosine ratio. Use the Pythagorean Theorem to find the value for the "opposite" side. Read off the value of the sine from the picture. :wink:
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Re: If cos 'theta' =1/2 the sin'theta' = WHAT?

Postby rere on Fri Jul 24, 2009 1:37 am

Yes, I am not sure what the question is asking for, I wrote it just as the problem said...Perhaps it is a typo
On the other, your advice helped me a lot. Thanks.
How about this problem;
If f9x0=x^2-x, which of the following is equal to x^2+x
A. f(x)+x
B. f(x)-x
C. -f(x)
D. f(-x)
E. [f(x)]^2
Thanks
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  TOPIC_SOLVED

Postby stapel_eliz on Fri Jul 24, 2009 3:53 pm

rere wrote:If f9x0=x^2-x, which of the following is equal to x^2+x

I will guess that the first bit is supposed to be

If so, try plugging into the various expressions, in places of , and find the one that matches. :wink:
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Re: If cos 'theta' =1/2 the sin'theta' = WHAT?

Postby pinkpuppi on Mon Sep 07, 2009 6:53 pm

the square root of three over 2. remember SOH CAH TOA. if you make a triangle with 'theta' as your angle then plug in the cos in the appropriate spots. 1 in the adjacent leg and 2 on the hypotonuse. this would create a 30 60 90 triangle, meaning the only available side should be root three. then take that over two for sin because that would be the opposit angle. hope that makes sense!
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