Help please...

If 90 degrees < 'theta' <180 degrees what is equaled to 5 cos 'theta' sec 'theta'?

and another...

If cos 'theta' =1/2 the sin'theta' = WHAT?

thank you for any advice and help.

Help please...

If 90 degrees < 'theta' <180 degrees what is equaled to 5 cos 'theta' sec 'theta'?

and another...

If cos 'theta' =1/2 the sin'theta' = WHAT?

thank you for any advice and help.

If 90 degrees < 'theta' <180 degrees what is equaled to 5 cos 'theta' sec 'theta'?

and another...

If cos 'theta' =1/2 the sin'theta' = WHAT?

thank you for any advice and help.

- stapel_eliz
**Posts:**1628**Joined:**Mon Dec 08, 2008 4:22 pm-
**Contact:**

rere wrote:If 90 degrees < 'theta' <180 degrees what is equaled to 5 cos 'theta' sec 'theta'?

I'm sorry, but I don't understand what this exercise is asking...? Are you supposed to find a range of value for the product of the 5, the cosine, and the secant? Or something else?

rere wrote:If cos 'theta' =1/2 the sin'theta' = WHAT?

Draw the right triangle. Label "adjacent" and "hypotenuse" sides with the values from the cosine ratio. Use the Pythagorean Theorem to find the value for the "opposite" side. Read off the value of the sine from the picture.

Yes, I am not sure what the question is asking for, I wrote it just as the problem said...Perhaps it is a typo

On the other, your advice helped me a lot. Thanks.

How about this problem;

If f9x0=x^2-x, which of the following is equal to x^2+x

A. f(x)+x

B. f(x)-x

C. -f(x)

D. f(-x)

E. [f(x)]^2

Thanks

On the other, your advice helped me a lot. Thanks.

How about this problem;

If f9x0=x^2-x, which of the following is equal to x^2+x

A. f(x)+x

B. f(x)-x

C. -f(x)

D. f(-x)

E. [f(x)]^2

Thanks

- stapel_eliz
**Posts:**1628**Joined:**Mon Dec 08, 2008 4:22 pm-
**Contact:**