## N = 00.00006x^3 + 0.006x^2 - 0.1x + 1.7. To nearest million,

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### N = 00.00006x^3 + 0.006x^2 - 0.1x + 1.7. To nearest million,

I need some serious help!

The number N, in millions, of hearing impaired persons of age X can be approximated by N= -0.00006x^3 + 0.0006x^2 - 0.1x + 1.7. Approximate to the nearest million the number of hearing impaired persons ages 35 and 50.
Pat Oliver

Posts: 9
Joined: Sat Apr 18, 2009 4:42 am

Pat Oliver wrote:The number N, in millions, of hearing impaired persons of age X can be approximated by N= -0.00006x^3 + 0.0006x^2 - 0.1x + 1.7. Approximate to the nearest million the number of hearing impaired persons ages 35 and 50.

To find the value, to the nearest million, of persons age x = 35, plug "35" in for "x". Round to the nearest whole number (since N is already in "millions").

To find the value, to the nearest million, of persons age x = 50, plug "50" in for "x". Round as above.

stapel_eliz

Posts: 1711
Joined: Mon Dec 08, 2008 4:22 pm

### Re: N = 00.00006x^3 + 0.006x^2 - 0.1x + 1.7. To nearest million,

Thanks stapel_eliz! I overlooked something soooo simple. Thats why they say 2 heads are better than one!
Pat Oliver

Posts: 9
Joined: Sat Apr 18, 2009 4:42 am