Exploring inequalities: Graph y< -x^2 + 4 on coord. plane

[nghiale2016]

Here is the problem
Graph y< -x^2 + 4 on a coordinate plane. Let y= 0 and solve for x and graph the solution a number line. Explain the relationship between the coordinate plane graph and the number line graph.

Please help me, thank you very much. :(

[stapel_eliz]

Where are you stuck in the process?

You've graphed the line "y = -x² + 4" (but as a dashed line, because this is not an "or equal to" inequality), you've plugged zero in for y and solved the quadratic equation for the values of x (being the x-intercepts of the graph), have picked the interval which solves the quadratic inequality, compared this interval with the graph, and... then what?

Please be specific. Thank you!

[nghiale2016]

The direction only said that I have to explain the relationship between the coordinate plane graph and the number line graph, I do not know how to do that :(, please help :(

[stapel_eliz]

You're to explain, after you've done the graph and the number line. What you need to do, once you've done the graph and the number line, is compare the graph's below-the-axis interval with the number line's solution interval.