## logs: Log3(x+1)-1=3+log(x-1), If x(square) + y (square) =23xy , prove that log x+y/5=1/2(log x+log y)

Complex numbers, rational functions, logarithms, sequences and series, matrix operations, etc.
Tabassum111
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### logs: Log3(x+1)-1=3+log(x-1), If x(square) + y (square) =23xy , prove that log x+y/5=1/2(log x+log y)

1. Log3(x+1)-1=3+log(x-1)
2.If x(square) + y (square) =23xy , prove that log x+y/5=1/2(log x+log y)

FWT
Posts: 153
Joined: Sat Feb 28, 2009 8:53 pm

### Re: logs: Log3(x+1)-1=3+log(x-1), If x(square) + y (square) =23xy , prove that log x+y/5=1/2(log x+log y)

1. Log3(x+1)-1=3+log(x-1)
The instructions said something like "solve the equation", right? Is there some significance to the one log being capitalized as "Log" and the other not being? Is the "3" after the "Log" a subscript, or part of the argument? What is the base of the other log?

To learn how to solve log equations in general, try here. But we can't help with this equation until we know more about it, so please reply with that info.
2.If x(square) + y (square) =23xy , prove that log x+y/5=1/2(log x+log y)
The "(square)" means "squared", right? So the first equation is x^2 + y^2 = 23xy, right?

In the second equation, is the "5" under the y only (as you've written it) or under the x also, so it's really (x + y)/5? Is the "log(x) + log(y)" part under the "1" with the "2", or not?

Tabassum111
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Joined: Wed Oct 12, 2016 6:40 am
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### Re: logs: Log3(x+1)-1=3+log(x-1), If x(square) + y (square) =23xy , prove that log x+y/5=1/2(log x+log y)

FWT
Posts: 153
Joined: Sat Feb 28, 2009 8:53 pm