Can someone explain how to do this problem, please?
(4n+1)!/(4n-1)!
Mere wrote:Can someone explain how to do this problem, please?
(4n+1)!/(4n-1)!
Mere wrote:So then... the denominator would be: 1x2x3x(4n-2)x(4n-1)
Mere wrote:And all of that would cancel out with the numerator, leaving (4n)x(4n+1), which is (16(n^2))+4n!