What you wrote means this:if I have 4e^2x + 5e^3x = 15
how do I solve for x?
How did you get to this step?I tried ln 4 +2x+ln5+3x=ln 15 but that doesn't work.
So you meant this:I meant b
Taking logs of both sides would give you this:and in order to solve say e^(2x) = Y I would take log of both sides so-
You're right! I think maybe "FWT" hadn't had his/her caffeine yet when s/he posted that!(a^b)(a^c)=(a^(b+c)) so above factoring won't work
Wolfram Alpha still gives a complicated answer. Assuming your equation is right, then maybe the homework is expecting a numerical approximation instead of an algebraic solution.difference of probabilities-actual numbers are
e^(-.16x)-e^(-.2x)=.5 solve for x