how do I solve for x given: 4e^-.2x + 3e^-.3x = 5

thanks

how do I solve for x given: 4e^-.2x + 3e^-.3x = 5

thanks

thanks

The way you've written it means this:how do I solve for x given: 4e^-.2x + 3e^-.3x = 5

a.

Did you mean this?

b.

Thanks.

b-thanks and the 5 should be .5

So you meant this:b-thanks and the 5 should be .5

Try using the steps, etc, explained in your other thread. The equations are pretty much the same so the methods will be pretty much the same too. If you get stuck, please write back showing what you did when working through the steps. Thanks.

- maggiemagnet
**Posts:**358**Joined:**Mon Dec 08, 2008 12:32 am-
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This one is at least as bad as your other one!how do I solve for x given: 4e^-.2x + 3e^-.3x = .5