please help me solve this logaritm. Log (x + 3) - log (x - 1) = log 2

- stapel_eliz
**Posts:**1628**Joined:**Mon Dec 08, 2008 4:22 pm-
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To start inLog (x + 3) - log (x - 1) = log 2

. . . . .

At which point, you have "log(something) = log(2)". Set "something" equal to 2, and

thank you. I ended up with x = 5. hope this is correct. thanks again!

- stapel_eliz
**Posts:**1628**Joined:**Mon Dec 08, 2008 4:22 pm-
**Contact:**