how do I solve log3(logx(log4^16))=-1
and also,
if log5=a and log36 = b, determine an expression for log 6/25 in terms of a and b
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How do I solve.... 
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How do I solve....
by rinkystinko on Mon Jul 13, 2009 9:50 pm
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by stapel_eliz on Tue Jul 14, 2009 2:29 am
Convert the outer log to the corresponding exponential equation. Simplify to get:
. . . . .logx(log4(16)) = 1/3
Use The Relationship to evaluate log4(16) = log4(42). See where that leads...
. . . . .logx(log4(16)) = 1/3
Use The Relationship to evaluate log4(16) = log4(42). See where that leads...
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stapel_eliz - Posts: 1705
- Joined: Mon Dec 08, 2008 4:22 pm
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