How do I solve....  TOPIC_SOLVED

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How do I solve....

Postby rinkystinko on Mon Jul 13, 2009 9:50 pm

how do I solve log3(logx(log4^16))=-1

and also,

if log5=a and log36 = b, determine an expression for log 6/25 in terms of a and b
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Postby stapel_eliz on Tue Jul 14, 2009 2:29 am

Convert the outer log to the corresponding exponential equation. Simplify to get:

. . . . .logx(log4(16)) = 1/3

Use The Relationship to evaluate log4(16) = log4(42). See where that leads... :wink:
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