Exponential wrote: log_4^(16/x)
- log_4^(16) - log4^ (x)
I will guess that the "to the power of" parts are actually the arguments of the logs, rather than powers on the bases, so the expression is as follows
:. . . . .
If so, then use a log rule
to expand the first term:. . . . .
The first and third terms cancel out, leaving you with:. . . . .