I'm asked to solve a problem with the equation 6^x = 24x^2

I thought it might begin thus:

6^x = (6)(4)x^2

6^x/6 = 4x^2

6^(x-1) = 4x^2

but I'm unsure if this is the correct technique or if another technique, (involving logarithms?) might be appropriate

I am not sure what to do about the right side of the equation. please help. thanks

postscript: answer given x = 3