The title pretty much states the problem. I'm trying to solve for x in 10^(3x-8) = 2^(5-x). The problem is that once I get it down to 3x-8 = 5 log 2 - x log 2, I don't know what to do. I continued trying to simplify it, and ended up with just having the other side log'ified, which was right back at square 1. Any help on this would be appreciated.