Solve log_6 (x+3) + log_6 (x+4) = 1, for X

Okay! I know the answer is -1, this is for my review. My issue is I don't know WHY the answer is -1. I can't work the problem to get that answer.

I move the second logarithm to the right side of the equation, getting log_6(x+3) = -log_6(x+4) + 1

And because the bases are the same, I set x+3 = -(x+4) + 1, but this works out to x=-3, which isn't the answer.

What am I doing wrong?