### Write as a single log: 2log6 - 4(log3 + log2)

Posted:

**Mon Mar 31, 2014 3:23 am**Write as a single log, please show working.

2log6 - 4(log3 + log2)

Here is what I got:

= log6^2 - log2^4 + log2^4

= log6^2 + log2^4 - log2^4

= log(6^2 + 2^4) - log3^4

= log52 - log 3^4

= log 52/81

2log6 - 4(log3 + log2)

Here is what I got:

= log6^2 - log2^4 + log2^4

= log6^2 + log2^4 - log2^4

= log(6^2 + 2^4) - log3^4

= log52 - log 3^4

= log 52/81