Write as a single log: 2log6 - 4(log3 + log2)

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Write as a single log: 2log6 - 4(log3 + log2)

Postby dgware on Mon Mar 31, 2014 3:23 am

Write as a single log, please show working.

2log6 - 4(log3 + log2)

Here is what I got:
= log6^2 - log2^4 + log2^4
= log6^2 + log2^4 - log2^4
= log(6^2 + 2^4) - log3^4
= log52 - log 3^4
= log 52/81
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Re: Write as a single log: 2log6 - 4(log3 + log2)

Postby theshadow on Tue Apr 01, 2014 11:28 am

dgware wrote:Write as a single log, please show working.

2log6 - 4(log3 + log2)

Here is what I got:
= log6^2 - log2^4 + log2^4

No. The 1st log is of 3, not of 2. Plus -4(log3 + log2) = -4(log3) - 4(log2). So fix the signs.
theshadow
 
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