Helping students gain understanding and self-confidence in algebra.
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by JC531 on Mon Mar 17, 2014 1:13 am
by Alfred on Mon Mar 17, 2014 5:27 am
by buddy on Mon Mar 17, 2014 11:59 am
JC531 wrote:ln(x2)=log5(x-1)I have no idea how to solve it.
by JC531 on Mon Mar 17, 2014 12:31 pm
by buddy on Mon Mar 17, 2014 10:15 pm
JC531 wrote:Could you go through steps on how you got to those and how to solve them? I wrote down what you put but I don't understand how you got to each equation.
by JC531 on Tue Mar 18, 2014 1:16 am
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