Simplifying Rational Functions: (x^4-3x^3-5x^2-7x+9)/(x^5-x^

Complex numbers, rational functions, logarithms, sequences and series, matrix operations, etc.
gem1110000
Posts: 5
Joined: Sat Apr 04, 2009 3:07 pm
Contact:

Simplifying Rational Functions: (x^4-3x^3-5x^2-7x+9)/(x^5-x^

Postby gem1110000 » Sat Apr 04, 2009 6:16 pm

X4-3X3-5X2-7X+9
------------------------
X5-X4-X3+3X2+5X+18

Help me this is so confusing to me! :confused: :?: :?:

User avatar
stapel_eliz
Posts: 1738
Joined: Mon Dec 08, 2008 4:22 pm
Contact:

Postby stapel_eliz » Sat Apr 04, 2009 6:36 pm

On what basis had you concluded that either of these polynomials was factorable...?

gem1110000
Posts: 5
Joined: Sat Apr 04, 2009 3:07 pm
Contact:

Re: Simplifying Rational Functions: (x^4-3x^3-5x^2-7x+9)/(x^5-x^

Postby gem1110000 » Sat Apr 04, 2009 6:38 pm

Ha the back of the book says (1/X+2) so I wana know how they got there.

User avatar
Martingale
Posts: 350
Joined: Mon Mar 30, 2009 1:30 pm
Location: USA
Contact:

Re: Simplifying Rational Functions: (x^4-3x^3-5x^2-7x+9)/(x^5-x^

Postby Martingale » Sat Apr 04, 2009 10:15 pm

did you type the question in correctly?

gem1110000
Posts: 5
Joined: Sat Apr 04, 2009 3:07 pm
Contact:

Re: Simplifying Rational Functions: (x^4-3x^3-5x^2-7x+9)/(x^5-x^

Postby gem1110000 » Sun Apr 05, 2009 1:50 am

oh dang its supposed to be +5x^2 in the top equation.

User avatar
stapel_eliz
Posts: 1738
Joined: Mon Dec 08, 2008 4:22 pm
Contact:

Postby stapel_eliz » Sun Apr 05, 2009 11:34 am

gem1110000 wrote:oh dang its supposed to be +5x^2 in the top equation.

Okay, well... now it appears that the numerator has no real factors, rational or otherwise. :shock:

gem1110000
Posts: 5
Joined: Sat Apr 04, 2009 3:07 pm
Contact:

Re: Simplifying Rational Functions: (x^4-3x^3-5x^2-7x+9)/(x^5-x^

Postby gem1110000 » Sun Apr 05, 2009 2:55 pm

WOW I feel so dumb right now it was just long division................ :!: :!: :!: :lol:

User avatar
stapel_eliz
Posts: 1738
Joined: Mon Dec 08, 2008 4:22 pm
Contact:

Postby stapel_eliz » Sun Apr 05, 2009 3:46 pm

gem1110000 wrote:I feel so dumb right now it was just long division.

Um... how are you supposed to do that...? :confused:

Since the denominator (the divisor) has a larger degree than the numerator (the dividend), you can't actually do any polynomial long division, at least not as currently presented. :shock:

Was the exercise perhaps to divide by ...? Because then the answer would be . :wink:


Return to “Advanced Algebra ("pre-calculus")”