y= ±2x+7

y= rad(5-x) (all under the rad)

y= 1/(x+62) - 2

y= -3^x + 41 (no parentheses around the -3 purposely)

how many are functions? this is what i think

no, yes, yes, yes

what do you think and why?

2 posts
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y= ±2x+7

y= rad(5-x) (all under the rad)

y= 1/(x+62) - 2

y= -3^x + 41 (no parentheses around the -3 purposely)

how many are functions? this is what i think

no, yes, yes, yes

what do you think and why?

y= rad(5-x) (all under the rad)

y= 1/(x+62) - 2

y= -3^x + 41 (no parentheses around the -3 purposely)

how many are functions? this is what i think

no, yes, yes, yes

what do you think and why?

- Hell0
**Posts:**16**Joined:**Sun Jun 23, 2013 5:04 am

Hell0 wrote:y= ±2x+7

y= rad(5-x) (all under the rad)

y= 1/(x+62) - 2

y= -3^x + 41 (no parentheses around the -3 purposely)

how many are functions? this is what i think

no, yes, yes, yes

what do you think and why?

I agree. Why? Because the last three match the definition of "function" but the first one doesn't.

- FWT
**Posts:**78**Joined:**Sat Feb 28, 2009 8:53 pm

2 posts
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