Helping students gain understanding and self-confidence in algebra.
cruxxfay wrote:No, that is the entire question.
cruxxfay wrote:Second question is
"Solve 2(5^(x+1)) = 1 + 3/(5^x), giving the answer in the form a + log(base 5) b, where a and b are integers"
I managed to solve for x, but I have no idea how to put it in the form a + log(base 5) b.... In fact this is what I got:
5^x = 3/5
x = log(base5)^3/5
= log(base5)^3 - log(base5)^5
= -1 + log(base5)^3
so a = -1 and b = 3? I don't have the answer so I am not quite sure.