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by **sanman777** on Mon Mar 23, 2009 4:30 pm

lnx^2=x

solve graphically?

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by **stapel_eliz** on Mon Mar 23, 2009 5:03 pm

sanman777 wrote:lnx^2=x

solve graphically?

Graph f(x) = ln(x^2) (or (ln(x))^2; I can't tell which you mean).

Graph g(x) = x on the same axis system.

Locate their intersection point. That's your solution! :wink:

by **eewongjr@yahoo.com** on Thu Apr 09, 2009 9:21 pm

turn lnx^2=x into the exponential form, then graph it. Once graphed, graph the inverse in order to get lnx^2=x

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lnx^2=x

lnx^2=x

Re: lnx^2=x